Calculate the potential for the reaction below at 25ºC under the
following conditions:
[Fe+3 ]=0.0200M
[Sn+2 ]=0.0200M
[Fe+2 ]=1.50M
[Sn+4 ]=1.50M
2 Fe+3(aq) + Sn+2 (aq) → 2 Fe+2
(aq) + Sn+4 (aq)
E = Answer V
Calculate the potential for the reaction below at 25ºC under the following conditions: [Fe+3 ]=0.0200M [Sn+2...
Calculate the potential for the reaction below at 25ºC under the following conditions: [Fe+3 ]=0.0200M [Sn+2 ]=0.0200M [Fe+2 ]=1.50M [Sn+4 ]=1.50M 2 Fe+3(aq) + Sn+2 (aq) → 2 Fe+2 (aq) + Sn+4 (aq)
a)Calculate the potential for the reaction below at 25ºC under the following conditions: [MnO?¯ ]=0.0200M [Ni+2 ]=2.50M pH = 2.000 2 MnO?¯ (aq) + 8 H+ (aq) + 3 Ni (s) ? 2 MnO? (s) + 4 H?O (l) + 3 Ni+2 (aq)
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2 pts) a. Use the standard half-cell potentials listed below to calculate the standard cell potential (Eºcell) for 3 Sn(s) + 2 Fe* (aq) - 3 Sn2+ (aq) + 2 Fe(s) Sn 2(aq) + 2 e -Sn (s) E = -0.14 V Fe3+ (aq) + 3 e Fe(s) E° = -0.036 V A) -0.176 V B)-0.104 V C) +0.104 V D) +0.176 V b. Write...
Calculate the standard potential for the reaction shown below at 25º? Sn+4 (aq) + Cl – (aq) + 2 OH – (aq) ⟶ Sn+2 (aq) + ClO – (aq) + H2O (l) Eº = Answer V
What is the expected standard cell potential for the following unbalanced reaction under basic conditions? MnO4-(aq) + Fe+2(aq) ⟶ Fe+3 (aq) + MnO2(s) Given: Fe3+ + e− ⟶ Fe2+ E1/2= 0.771 MnO4−+ 2 H2O + 3e− ⟶ MnO2 + 4OH− E1/2 = 0.558 A. -0.213 V B. +0.213 V C. -1.329 V D. +1.329 V E. None of the above
u Calculate the standard cell potential for each reaction below, andnote whether the reaction is spontaneous under standard state conditions. 1. Mn(s)+Sn(NO3)2(aq)⟶Mn(NO3)2(aq)+Sn(s) 2. Na(s)+LiNO3(aq)⟶NaNO3(aq)+Li(s) ● 3. Mg(?)+Ni2+(??)⟶Mg2+(??)+Ni(?)
1) Balance the following reaction under acidic conditions and calculate the cell potential in (V) at 298 K generated by the cell. Report your answer to the hundredths place. Cr2O72-(aq) + I-(aq) → Cr3+(aq) + I2(s) [Cr2O72-] = 2.0 M, [H+] = 1.0 M, [I-] = 1.0 M, [Cr3+] = 1.0 × 10-5 M 2) What is the value of n for the following reaction? Enter the whole number. 3Ni+(aq) + Cr(OH)3(s) + 5OH-(aq) → 3Ni(s) + CrO42-(aq) + 4H2O(l)
Half-reaction Cr3+ (aq) + 3e--Cr(s) Fe2+ (aq) + 2e - Fe(s) Fe3+ (aq) - Fe2+ (5) Sn+ (aq) + 2e - Sn2(aq) E (V) -0.74 -0.440 +0.771 +0.154 1. Calculate the standard cell potential for the voltaic cell based on the reaction below, given the table above: 35nt(s) + 2Cr (s) - 2 C (s) + 3 Sn () ANSWER: 2. Calculate the standard cell potential for the voltaic cell based on the reaction below, Riven the table above 3Feb...
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential Fe+3(aq) +e− → Fe+2(aq) =E0red+0.771V 2H2O(l) +2e− → H2(g) + 2OH−(aq) =E0red−0.83V Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you...
Calculate the standard cell potential for the following reaction. Fe (s) +Ni^+2 (aq) rightarrow Fe^+ 2 (aq) + Ni (s) 3 Cu + 2 NO_3^- + 8 H^+ rightarrow 3 Cu^+ 2+ 2 NO +4 H_2O Cr_2O_7^-2 + 6 Fe^+2+14 H6+ rightarrow 2 Cr^+ 3 + 6 Fe^+ 3 +7 H_2O