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One mole of an ideal gas initially at a temperature of Ti = 5°C undergoes an...

One mole of an ideal gas initially at a temperature of Ti = 5°C undergoes an expansion at a constant pressure of 1.00atm to four times its original volume

Tf is 1101

Calculate the work done on the gas during the expansion.

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Answer #1

Work done by the gas is given by PdV i.e. pressure x change in volume

since PdV = nRdT hence

work done = nR(T1-T2)

= 1x8.31x(1101-5)

=9107 J

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