monobasic sodium phosphate NaH2PO4 is the weak acid.
dibasic sodium phosphate Na2HPO4 is the conjugate base.
Ka = 6.2 x 10-8
pKa = -log(Ka)
pKa = -log(6.2 x 10-8)
pKa = 7.2
According to Henderson - Hasselbalch equation,
pH = pKa + log([conjugate base] / [weak acid])
pH = pKa + log([Na2HPO4] / [NaH2PO4])
pH = 7.2 + log(1 M / 1 M)
pH = 7.2 + log(1)
pH = 7.2 + 0
pH = 7.2
pH of solution is 7.2
What is the pH of a solition that is 1M in each of monobasic and dibasic...
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