Write a function, named display_count_dict, that when given a my_count dictionary, representing a key with its value being a count, displays the dictionary with key and count so that the key having the highest count is displayed, first. Sample:my_counts{"A":3, "D":3, "B": 7, "E": 2, "C"10}
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def display_count_dict(my_count):
keyval={}
for i,j in my_count.items():
keyval[i]=j
return sorted(keyval.items(),key= lambda values:(values[1],
values[0]),reverse = True)
dictionary={"a": 4,"b":3, "c":2,"d":1}
print(display_count_dict(dictionary))

Write a function, named display_count_dict, that when given a my_count dictionary, representing a key with its...
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