Calculate the pH of a solution containing 0.10 mole of acetic acid, to which is added 0.03 mole of sodium hydroxide (Ka = 1.8 x 10-5).
Moles of sodium acetate formed= 0.03 mol
Excess mole of acetic acid = 0.10-0.03=0.07 mol
It is acidic buffer,
pH = pKa + log(salt/acid)
= 4.74+log(0.03/0.07)
= 4.38
Calculate the pH of a solution containing 0.10 mole of acetic acid, to which is added...
(C))3.75 moo (D) 4.75 (E) 5.75 bios nA oir 9. Ka of acetic acid is 1.8 x 10. What is the pH of a solution 0.1M acetic acid and 0.05M sodium acetate? (A) 4.44 oasd A (B) 4.74 (C) 4.96 (D) 5.04 (E) 5.56 10. A buffer solution containing 0.5M acetic acid and 0.5M sodium acetate hais a pH ot 4.745. 5ml 2M sodium hydroxide is added to 995ml of the buffer solution. What is final pH? (A) 4.569
(C))3.75...
A buffer solution that is 0.10 M sodium acetate and 0.20 M acetic acid is prepared. Calculate the initial pH of this solution The K, for CH3COOH is 1.8 x 10-5 M. As usual, report pH to 2 decimal places. Answer: A buffered solution resists a change in pH. Calculate the pH when 21.2 mL of 0.031 M HCl is added to 100.0 mL of the above buffer. Answer:
1) Calculate the pH in the titration of 50.00 mL of 0.060 M acetic acid (CH3COOH) with a 0.120 M sodium hydroxide, NaOH solution after the addition of the following volumes of base: Ka for acetic acid = 1.8 x 10-5 A) 0 mL pH = B) 10 ml pH =
Solid NaOH is added to a solution of 0.50 M acetic acid until the pH of the solution is 4.30. The resulting concentration (M) of sodium acetate in the solution is Ka (CH3COOH) = 1.8 x 10-5 A. 0.020 B. 0.13 C. 0.30 D. 5.0 x 10-5 E. 0.50
Calculate the pH, the percent dissociation, and the concentration of OH- in 0.10 M of Acetic Acid solution (HC2H3O2) (Ka = 1.8 x 10^-5) (Kw = 1.0 x 10^-14)
What would the concentration of acetic acid need to be in a solution containing 0.25 M sodium acetate to have a pH of 4.0? Given that Ka for acetic acid is 1.8 × 10-5.
a buffer solution of pH =5.30 can be prepared by dissolving acetic acid and sodium acetate in water. How many moles of sodium acetate must be added to 1 L of 0.25 M acetic acid to prepare the buffer? Ka(CH3COOH)=1.8 x 10^-5
What is the pH of a solution prepared by mixing: 0.30 moles of acetic acid (Ka = 1.8 X 10-5) 0.15 moles of sodium hydroxide in 1.0 L of solution A. 4.44 B. 13.18 C. none of the above D. 0.82 E. 4.74
25 mL of 0.10 M acetic acid is titrated with 0.10 M NaOH. What is the pH after 30 ml of NaOH have been added? Ka for acetic acid = 1.8 x 10^-5.
i need help with 6 b) please
6. a) Calculate the pH of a solution prepared by dissolving 0.0775 mol acetic acid and 0.0460 mol sodium acetate in 1 L of water. (Ka = 1.8 x 10-5) ANSWER: 4.52 b) Calculate the pH of the above solution if 0.0100 mol of KOH is added to this solution. ANSWER: 4.66