What is the molarity of 150.0 mL of solution that contains 0.0300 mol of glucose?

Question

Question

science chemistry

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

12) 250 ml of glucose solution contains 18.016 g of solute. what is the molarity of...

12) 250 ml of glucose solution contains 18.016 g of solute. what is the molarity of the solution? (MW glucose 180.16 g/mol)
calculate the molarity of a solution if 150.0 ml of it contains 8.4 g og KNO3

calculate the molarity of a solution if 150.0 ml of it contains 8.4 g og KNO3
You titrated a 22.00 mL solution of 0.0300 M oxalic acid with freshly prepared solution of...

You titrated a 22.00 mL solution of 0.0300 M oxalic acid with freshly prepared solution of KMnO4. If it took 48.99 mL of this solution, what is the molarity of the KMnO4? 0.022 L of 0.300 M oxalic acid (0.022)(0.03) = 0.00066 mol oxalic acid 0.0006 mol oxalic acid x (2 mol KMnO4)/(5 mol oxalic acid)= 0.000264 mol KMnO4 0.000264 mol/0.04899 L = 0.05388855 M KMnO4 = 0.005388 M KMnO4 where did I go wrong? Question 7 0.1 / 1...

What molarity of KBr (MM = 119.0 g/mol) is a 500. mL solution that contains 17.2...

What molarity of KBr (MM = 119.0 g/mol) is a 500. mL solution that contains 17.2 g of KBr?
What are the molarity, molality, X of a 6.56% by mass glucose (C6H12O6, MM=180g/mol) solution? The...

What are the molarity, molality, X of a 6.56% by mass glucose (C6H12O6, MM=180g/mol) solution? The density of the solution is 1.03g/mL.
Calculate the molarity of each of the following ions. 0.733 g Na+ in 150.0 mL of...

Calculate the molarity of each of the following ions. 0.733 g Na+ in 150.0 mL of a NaCl solution. ___M 0.480 g of Cl– in a 150.0 mL of a NaCl solution. ___M 0.360 g of SO42– in 150.0 mL of Na2SO4 solution. ___M 0.290 g of Ca2+ in 150.0 mL of CaCl2 solution. ___M

A solution contains 1.65 g of NaF in a total volume of 150.0 mL what is...

A solution contains 1.65 g of NaF in a total volume of 150.0 mL what is its concentration expressed as % (m/V)?
A solution is prepared by dissolving 47.8 grams of glucose (180.16 g/mol) in 0.159 kilograms of water. The final volume of the solution is 441 mL . Calculate the molarity of the solution.

A solution is prepared by dissolving 47.8 grams of glucose (180.16 g/mol) in 0.159 kilograms of water. The final volume of the solution is 441 mL . Calculate the molarity of the solution.
Calculate the molarity of the two solutions. The first solution contains 0.500 mol of NaOH in...

Calculate the molarity of the two solutions. The first solution contains 0.500 mol of NaOH in 1.35 L of solution. molarity: The second solution contains 10.1 g of NaCl in 681 mL of solution. molarity:

Calculate the molarity of the two solutions. The first solution contains 0.650 mol of NaOH in...

Calculate the molarity of the two solutions. The first solution contains 0.650 mol of NaOH in 1.40 L of solution. molarity: 0.464 The second solution contains 17.7 g of NaCl in 811 mL of solution. molarity: 0.360