Flux density of magnetic field B around a current carrying wire is given by,

Hence flux density of magnetic field at a radial distance r,
B(r) = (
I ) / (
2
r)
.............(1)
For magnetic field inside wire, current I is calculated as shown below

Let us consider the cross section of wire as shown in figure. Current I is uniformly distributed
Current passing through the cross section of radius r is obtained as

where j is current density across the area of cross section, j =
I / (
a2)
since a = 1, current passing through the cross section of radius r in side wire ( r < a ) is given by
Ir = (1/
)
r2 =
r2
Hence flux density of magnetic field inside wire ,
B(r) = [ (
) / ( 2
r) ]
r2 = [
/
(2
) ] r , .......r
a
Flux density of magnetic field outside the wire,
B(r) = [
/
(2
r) ]
........ r > a
Plot of flux density of magnetic field is given below

Derive the magnetic field B inside and outside of an infinite thick wire with radius a=1....
The long, thin wire shown in the figure (Figure 1) is in a
region of constant magnetic field B⃗ . The wire carries a
current of 6.2 A and is oriented at an angle of 7.5° to the
direction of the magnetic field. A) If the magnetic force exerted
on this wire per meter is 3.3×10-2 N , what is the
magnitude of the magnetic field? B) At what angle will the force exerted on the
wire per meter be equal to...
TA) Q4: Time (30 minutes) A. The current flowing in a solenoid, of 400 turns, 20 cm length & 4 cm diameter, changes with time according to the graph show to right. Derive an expression for the strength of the induced electric field inside the solenoid 0 00 01 02 03 04 Sketch the corresponding graph showing how the induced electric field vary with time. B. The Figure to right shows an infinite straight wire carries a current I is...