Question

C++ Part 2: Rock Paper Scissors Game Write a program that lets the user play this...

C++

Part 2: Rock Paper Scissors Game

Write a program that lets the user play this game against the computer. The program should work as follows:

  • When the program begins, a random number between 1 and 3 is generated.
    • If the number is 1, the computer has chosen rock.
    • If the number is 2, the computer has chosen paper.
    • If the number is 3, the computer has chosen scissors.
    • Don't display the computer's choice yet.
  • Use a menu to display the choices the user can enter.
  • Prompt the user to enter his or her choice of rock, paper or scissors.
  • Display the computer's choice and the user’s choice.
  • Select a winner according to the following rules:
    • Rock smashes scissors, so rock wins.
    • Scissors cuts paper, so scissors wins.
    • Paper wraps rock, so paper wins.
    • If both players make same choice, game must be played again to determine winner.

Divide program into functions to perform each major task. You should have at least 4 functions.

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Answer #1

Feel free to ask any doubts and give feedback!

The code cotains comments to help you understand

OUTPUT:

CODE:

#include<iostream>

#include<stdlib.h>

#include<time.h>

using namespace std;

int main()

{

//set current time as random seed

srand(time(0));

//infinite loop

while(1)

{

//generate a ranom number using rand()

//rand()%(3-1+1) returns a random number between 0 and 2

//adding 1 will give us desired random number

//cc is computer's choice

int cc=(rand()%(3-1+1))+1;

//enter user's choice

int uc;

cout<<"Enter rock,paper or scissor(1,2,3)\n";

cin>>uc;

//case 1

if(cc==1 && uc==3)

{

cout<<"Compuer won\n";

}

else if(uc==1 && cc==3)

{

cout<<"You won!\n";

}

//case 2

else if(cc==3 && uc==2)

{

cout<<"Compuer won\n";

}

else if(uc==3 && cc==2)

{

cout<<"You won!\n";

}

//case 3

else if(cc==2 && uc==1)

{

cout<<"Compuer won\n";

}

else if(uc==2 && cc==1)

{

cout<<"You won!\n";

}

//last case

else if(uc==cc)

{

//dont break from the loop if uc=cc

continue;

}

else

{

//nothing

}

//break if everything went as expected

break;

}

return 0;

}

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