Question

2. Write a counter controlled loop to solve the following problems. Each one will involve an array

(MinMax.java) Read in 25 ints from the keyboard, and store them in an array. Then, find the maximum and minimum values in such an array, and display them on the screen.

public class Array-Assignment {

public static void main(String [] args) {

    int [] x = new int[3];

    int [] y = {3, 5, 9, 2};

    x[2] = y[3];

    x[0]++;

    y[1] += y[2] * y[0];

    int [] z = x;

x = y;

x[1] = 4;

}

}

public class Array-Length {

public static void main(String [] args) {

    int [] x = new int[4];

    int [] y = {};

    int [] z = {0};

    System.out.println("x has " + x.length + " elements");

    System.out.println("y has " + y.length + " elements");

    System.out.println("z has " + z.length + " elements");

}

}

public class Array-With-Loop1 {

public static void main(String [] args) {

    int [] x = {-4, 9, 8, 2, -5, 7, 1};

    for(int i=1; i

      x[i] += x[i-1]; // notice: += instead of =

    }

}

}

public class Array-With-Loop2 {

public static void main(String [] args) {

    int [] x = {-4, 9, 8, 2, -5, 7, 1};

    for(int i=1; i

      x[i] = x[i-1];

    }

}

}

public class Array-With-Loop3 {

public static void main(String [] args) {

    int [] x = {-4, 9, 8, 2, -5, 7, 1};

    int val = 0;

    for(int i=1; i

      val = val + x[i];

    }

}

}

Answer 1

Code is after the output.

Please feel free to ask doubt/give feedback.

Output:

Answer:

import java.util.Scanner;

public class MinMax{

public static void main(String args[])

{

//create an array of size 25

int a[]=new int[25];

//declare min and max varibales

int min,max;

//create a scanner object to take input from the keyboard

Scanner sc=new Scanner(System.in);

System.out.println("Enter 25 integers");

//for loop, 25 times

for(int i=0;i<25;i++)

{

//scan a[i]

a[i]=sc.nextInt();

}

//initialize min and max to first item of the array

min=max=a[0];

//loop through the items of the array

for(int i=0;i<25;i++)

{

//use Math.min and Math.max to find min/max between previous min/max and a[i]

min=Math.min(min,a[i]);

max=Math.max(max,a[i]);

}

//print the result

System.out.println("Maximum number is "+max+"\nMinimum number is "+min);

}

}