The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the...
The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the field lines make an angle of 13.0º with the plane of the surface. What is the electric flux when the angle is changed to 77.0º? (Enter units as Nm^2/C or Vm
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The electric flux from a uniform field through a flat
surface is 7.80 N·m2/C when the...
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area...
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
There is an electric flux of 24.5 N·m2 C through the square region shown in the...
There is an electric flux of 24.5 N·m2 C through the square region shown in the figure to the right. Each side of the square has a length of 0.100 m, and the electric field is at an angle of = 61.0° relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude of the electric field? Le , lit. Number N/C
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area...
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area of 0.62 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?
A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field...
A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field given by E= 5.1i^+2.1j^+3.5k^ kN/C. find the flux through this surface
A uniform electric field measured over a square surface with side length d = 13.5 cm...
A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C
Consider the uniform electric field } = (2.0ġ + 7. Ok) 103 N/C. (a) What is...
Consider the uniform electric field } = (2.0ġ + 7. Ok) 103 N/C. (a) What is its electric flux (in N.m2/C) through a circular area of radius 1.6 m that lies in the yz-plane? (Enter the magnitude.) 0 N·m2/C (b) What is its electric flux (in N·m-/C) through a circular area of radius 1.6 m that lies 45.0° above the xy-plane? (Assume that the unit normal vector is n = (î+k).) 51200 X N·m2/C
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface...
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface (a) What type of charge distribution is inside the surface? C a positive line charge situated on and parallel to the axis of the cylinder O a negatively charged plane parallel to the end faces of the cylinder C a positively charged plane parallel to the end faces of the cylinder a collection of negative point charges arranged in a line at the center...
A circular loop of radius 11.0 cm is placed in a uniform electric field given by...
A circular loop of radius 11.0 cm is placed in a uniform electric field given by E = (7.80 ✕ 105 N/C)k. What is the electric flux through the loop if it is oriented in the following ways? (Enter the magnitude.) (a) parallel to the xy plane ___N · m2/C (b) parallel to the xz plane ___N · m2/C (c) What is the electric flux through the loop if it is oriented at a 45.0° angle to the xy plane?...
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
There is an electric flux of 24.5 N·m2 C through the square region shown in the figure to the right. Each side of the square has a length of 0.100 m, and the electric field is at an angle of = 61.0° relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude of the electric field? Le , lit. Number N/C
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C
Consider the uniform electric field } = (2.0ġ + 7. Ok) 103 N/C. (a) What is its electric flux (in N.m2/C) through a circular area of radius 1.6 m that lies in the yz-plane? (Enter the magnitude.) 0 N·m2/C (b) What is its electric flux (in N·m-/C) through a circular area of radius 1.6 m that lies 45.0° above the xy-plane? (Assume that the unit normal vector is n = (î+k).) 51200 X N·m2/C
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface (a) What type of charge distribution is inside the surface? C a positive line charge situated on and parallel to the axis of the cylinder O a negatively charged plane parallel to the end faces of the cylinder C a positively charged plane parallel to the end faces of the cylinder a collection of negative point charges arranged in a line at the center...
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