Question

JAVA

1.Write a static method named getMaxEven(numbers) which takes an array of positive integers as a parameter. This method calculates and returns the largest even number in the list. If there are no even numbers in the array, the method should return 0. You can assume that the array is not empty.

For example:

Test	Result
int[] values = {1, 4, 5, 9}; System.out.println(getMaxEven(values));	4
System.out.println(getMaxEven(new int[]{1, 3, 5, 9}));	0

public static int

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2.

Write a static method named noEven(values) that takes an array of integers as a parameter and returns true if all of the integers in the array are odd, and false otherwise. You can assume that the array is not empty and the method returns a boolean value.

For example:

Test	Result
System.out.println(noEven(new int[]{2, 3, 4, 5, 6}));	false
System.out.println(noEven(new int[]{1, 3, 5, 7}));	true

public static boolean

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3.

Write a static method named repeats_exist(numbers) that takes an array of integers as a parameter and returns true if there are any repeated values in the array, and false if all of the values in the array are unique. Note: you can assume that the array is not empty and the method returns a boolean value.

For example:

Test	Result
System.out.println(repeats_exist(new int[]{2, 3, 4, 5, 6}));	false
System.out.println(repeats_exist(new int[]{2, 3, 4, 3, 6}));	true

public static boolean

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These three are separate questions，please complete them one by one. Thx~

Answer 1

Answer 1) The code of this question is below:

public class Main
{
public static int getMaxEven(int [] arr){
  
int [] evenArray=new int[10];
int num;
for (int i = 0, j=0; i < arr.length; i++) {
  
if(arr[i] % 2 == 0){
evenArray[j] = arr[i];
j++;
}
}
int maxEven=0;
for (int i = 0; i < evenArray.length; i++){
if( evenArray[i] > maxEven )
maxEven=evenArray[i];
}
return maxEven;
}
   public static void main(String[] args) {
       int[] values1 = {1, 4, 5, 9};
       System.out.println(getMaxEven(values1));
      
       int[] values2 = {1, 3, 5, 9};
       System.out.println(getMaxEven(values2));
   }
}

CODE AND OUTPUT SCREENSHOT

Answer 2) The Code for this question is below:

public class Main
{
public static boolean noEven(int [] arr)
{
boolean odd=true;
for (int i = 0; i < arr.length; i++) {
  
if(arr[i] % 2 == 0){
odd=false;
}
}
return odd;
}
   public static void main(String[] args) {
      
       System.out.println(noEven(new int[]{2, 3, 4, 5, 6}));
System.out.println(noEven(new int[]{1, 3, 5, 7}));
      
   }
}

CODE AND OUTPUT SCREENSHOT