How does adding water to antimony trichloride affect (shift) the equilibrium even though it doesn't show up on the equalibrium constant expression? Is it because it dilutes the concentrations of the Cl- ions? Which way does it shift?
SbCl3 (aq) + H20(l) <---> SbOCl(s) + 2H+(aq) + Cl-(aq)
SbCl3(aq) + H2O (l) -----------------------> SbOCl (s) +
2 H+ (aq) + Cl-(aq)
here the equilbrium will not effected by the pure solids and liquids concentrations
and here the more H2O i.e pure liquid is added it does not affect the equilibrium position i.e equilibrium does not shift either right or left and does not change their concentrations
answer => pure liquids and pure solids are taken as unity while writing the Kc expression
pure liquid is added it does not affect the equilibrium position i.e equilibrium does not shift either right or left and does not change their concentrations
How does adding water to antimony trichloride affect (shift) the equilibrium even though it doesn't show...
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1.How does adding NaOH to deionized water affect the pH differently
than adding it to a buffer?
2. how would you find the Ka of solution 4, after it is
diluted from solution 3? the measured pH was 4.98 which gave a [H+]
concentration of 1.05x10^-5.
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help please?
this was the only other information given
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Titration: Acids and Bases
2. How can you determine which acid is diprotic?
3. using the answers to questions one and two, which acid is
diprotic?
4. Which base has more hydroxide ions per molecule?
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For the preparation and standardization of NaOH with KHP im supposed to boil water for 1hr and 30 min to remove CO2....the problem is that if I don't boil it for that long and (30 min) b/c of not enough time but I put the water I boiled for 1/2 hr aproximately into a NaOH bottle with a CO2 absorber and stored it there for a few days. I would assume that I would have to boil the water again...but...