Question

What is the molarity of a 14.5% by mass glucose (C6H12O6) solution? (The density of the solution is 1.03 g/mL.)

Answer 1

Here is the solution of your question. If you have any doubt or need any clarification please comment in comment box and will definitely resolve your query. If you find useful please upvote it. Thanks in advance.

Answer 2

To determine the molarity of the glucose solution, we need to first calculate the moles of glucose present in 1 liter of the solution.

Given:

• The solution is 14.5% by mass glucose, which means 100 g of the solution contains 14.5 g of glucose.

• The density of the solution is 1.03 g/mL, which means 1 liter of the solution weighs 1030 g.

Using the above information, we can calculate the moles of glucose as follows:

Mass of glucose in 1 liter of the solution = (14.5 g/100 g) x 1030 g = 149.35 g Moles of glucose = Mass of glucose/Molar mass of glucose = 149.35 g/180.16 g/mol = 0.8298 mol

Therefore, the molarity of the glucose solution is:

Molarity = Moles of solute/Volume of solution in liters Molarity = 0.8298 mol/1 L = 0.8298 M

So the molarity of the solution is 0.8298 M.