Question

To four significant figures, a) what is the energy of a photon emitted from a hydrogen atom when an electron makes a transition from n=6 to n=2

b) find the energy of electromagnetic radiation necessary for ionization (transition to n=invinity) of the 1s1 electron in a hydrogen atom?

Please help step by step so I can duplicate it.

Thank you

Answer 1

a.

Rydberg equation is

= R_H × ( )

R_H is Rydberg constant. h is planck constant , c is velocity of light.

n_i =2

n_f = 6

or, E = R_{​​​​​​H} × h× c× ()

or, E = 1.09737 × 10⁷ × 6.626×10^-34 ×3×10⁸ ×(2/9)

or, E = 4.847 ×10^-19 J.

hence, energy of photon emitted = 4.847×10^-19 J.

b.

n_i = 1

n_f = infinity

E = R_H × C× h × ( )

or, E = 1.09737×10⁷ ×6.626×10^-34 × 3×10⁸ ×1

or, E = 2.181×10^-18 J.