Question

Consider the following elementary step

X + 2Y

→

XY₂

If the initial rate of formation of XY₂ is 0.0026 M/s and the initial concentrations of X and Y are 0.66 Mand 0.76 M, what is the rate constant for the reaction?

Answer will be in M^-2s^-1

Thank you

Answer 1

Given reaction is the form of

X + 2 Y --> XY2

Rate of the reaction is the speed at which the reactants is converted to products.

So Rate of Reaction is given by:

Rate = k [X] [Y]^2, where k is the rate constant.

Here, Rate = 0.0026 M/s

[X] = 0.66 M

[ Y ] = 0.76 M

So k = Rate/ [ X] [Y]^2

k = 0.0026/ 0.66* (0.76) ^ 2

= 0.0022754 M^-2 s^ -1.. . Answer