We have been given the history of shipping costs below. You have been asked to calculate a linear trend line for this data. W
hat is the intermediate solution for the value of b? (Your answer should be an integer)
Week Costs
week 1. 497430
week 2. 500072
week 3. 535584
week 4. 514058
Let’s assume that the linear trend equation for shipping costs is represented by the following equation
y = a + b *t…………………….. (1)
Where a is the y-intercept of the line and b is the slope of the line. Formula to calculate the a and b are following
Slop b = (n * Σty – Σt * Σy) / {n * Σ (t^2) - (Σt) ^2}
Intercept a = (Σy – b * Σt) / n
Where,
n is number of period = 4 (number of weeks)
Σy is the sum of total costs
Σt is the sum of weeks
Σty is the sum of total costs * weeks
Σt^2 is the sum of squares of weeks
|
Week (t) |
Cost (y) |
y*t |
t^2 |
|
|
1 |
497430 |
497430 |
1 |
|
|
2 |
500072 |
1000144 |
4 |
|
|
3 |
535584 |
1606752 |
9 |
|
|
4 |
514058 |
2056232 |
16 |
|
|
Sum |
10 |
2047144 |
5160558 |
30 |
Now, Slop b = (n * Σty – Σt * Σy) / {n * Σ (t^2) - (Σt) ^2}
= (4 * 5160558 – 10 * 2047144) / (4 * 30 – 10^2) =8540
Therefore value of b is 8540
And Intercept a = (Σy – b * Σt) / n = (2047144 – 8540 * 10)/4 = 490437
Now putting the value of a & b in equation (1), we get linear trend equation
Y = 490437 + 8540 * t
We have been given the history of shipping costs below. You have been asked to calculate...
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