Question

A particle of mass 2 kg is moving in the xy plane at a constant speed of 0.80 m/s in the +x direction along the line y=4m.  As the particle travels from ,x= -3m to x= +3m, the magnitude of its angular momentum with respect to the origin is

A] not constant

B] 0

C} 4.8 kg m²/s

D} 8.4 kg m²/s

E} 8 kg m²/s

Answer 1

Solution :

Since the Angular momentum is given by :

L = m v r

Here,

m = 2 kg

v = 0.80 m/s

r = 4 m

Thus : L = (2 kg)(0.80 m/s)(4 m) = 6.4 kg m² / s