Question

Using bash script write a function named join_with that will join the positional parameters with a character. The function would work like this:

join_with "," 1 2 3 4 5

1,2,3,4,5

join_with "-" 12 34 56 78

12-34-56-78

join_with ":" {a..z}

a:b:c:d:e:f:g:h:i:j:k:l:m:n:o:p:q:r:s:t:u:v:w:x:y:z

Answer 1

Code:

Output:

Raw Code:

#!/bin/bash

join_with () {
   all=$(IFS=$1 eval 'echo "$*"'); # joining the all arguments with given delimiter
   echo "${all[@]:2}" # Eliminating the delimiter at the first place
}

# Calling function with different cases:
join_with "," 1 2 3 4 5
join_with "-" 12 34 56 78
join_with ":" {a..z}

If you have any doubts plz ask in comment section.