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The test statistic of zequals=2.952.95 is obtained when testing the claim that pnot equals≠0.4970.497. a. Identify...

The test statistic of zequals=2.952.95 is obtained when testing the claim that pnot equals≠0.4970.497. a. Identify the hypothesis test as being​ two-tailed, left-tailed, or​ right-tailed. b. Find the​ P-value. c. Using a significance level of alphaαequals=0.010.01​, should we reject Upper H 0H0 or should we fail to reject Upper H 0H0​? Click here to view page 1 of the standard normal distribution table. LOADING... Click here to view page 2 of the standard normal distribution table. LOADING... a. This is a ▼ right-tailed two-tailed left-tailed test. b.​ P-valueequals=nothing ​(Round to three decimal places as​ needed.) c. Choose the correct conclusion below. A. Fail to rejectFail to reject Upper H 0H0. There isis sufficient evidence to support the claim that pnot equals≠0.4970.497. B. Fail to rejectFail to reject Upper H 0H0. There is notis not sufficient evidence to support the claim that pnot equals≠0.4970.497. C. RejectReject Upper H 0H0. There is notis not sufficient evidence to support the claim that pnot equals≠0.4970.497. D. RejectReject Upper H 0H0. There isis sufficient evidence to support the claim that pnot equals≠0.4970.497.

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Answer #1

a. Here we see that alternative hypothesis have inequality sign, which means it is two tailed test

Hence answer is This is two tailed test

b. z test statistics is z=2.95, so P value is

c. As P value is less than , we reject the null hypothesis

So answer here is D. Reject Upper H0. There is sufficient evidence to support the claim that p not equals≠0.497.

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