Which of the following would be the mean of this data set: 5, 28, 12, 56,...

Question

Question

Which of the following would be the mean of this data set: 5, 28, 12, 56, 4, 2, 30, 21

18.24

19.75

17.06

16.50

math Statistics-And-Probability

Answer 1

Answer #1

solution:

The mean of sample is

x/n = (5+ 28+ 12+ 56+4+ 2+ 30+ 21/ 8)

=19.75

Answer 2

Similar Homework Help Questions

Find the mean for the following data set: 11 12 22 16 28

Find the mean for the following data set: 11 12 22 16 28
Data set (observations) : 28 30 30 29 12 28 31 32 mean: 27.5 standard deviation:...

Data set (observations) : 28 30 30 29 12 28 31 32 mean: 27.5 standard deviation: 6.887 a) how many observations are within 2 standard deviations from the mean? b) are there any outliers in this dataset? name 3 things we might do with an outlier
Find the mean of the following data set: 27, 28, 30, 41, 43, 44, 45, 51,...

Find the mean of the following data set: 27, 28, 30, 41, 43, 44, 45, 51, 51, 53, 53, 54, 56, 56, 56, 57, 57, 58, 58, 59, 61, 62, 62, 62, 63, 64, 67, 68, 68, 68, 69, 69, 74 68 57 55.58

Which of the following is an example of a data set with 5 values for which...

Which of the following is an example of a data set with 5 values for which the standard deviation is zero. a-2,-1,0,1,2 b) 4,4,44,4 )1,2,3,4,5 d -5,-3,0,3,5 Question 5 If the test scores of a class of 35 students have a mean of 71.1 and the test scores of another class of 28 students have a mean of 67.4, then the mean of the combined group is a67.750 b 69.250 c69.456 66.956
2 (f) If a new grade, Y, is added to the data set, so the data set becomes 12, 78, 24, 28, 42, 60...

2 (f) If a new grade, Y, is added to the data set, so the data set becomes 12, 78, 24, 28, 42, 60, 94, 62, 68, Y (where Y is the new grade), what is the maximum amount by which the new median could differ from the old median (in 2(a))? (This means, if the new median is mnew and the old median that you found in 2(a) was mold, what is the maximum value that |mnew−mold|can have? Here,...
Consider the following data set 20 23 27 21 25 21 24 17 12 28 21...

Consider the following data set 20 23 27 21 25 21 24 17 12 28 21 23 12 a) Determine the quartiles for this data. b) Determine the interquartile range for this data. a) The first quartile is the second quartile is □, and the third quartile is (Type integers or decimals.)

ELT041 Calculate the mean variance of the following set of hourly tank levels: 1:00 - 28%...

ELT041 Calculate the mean variance of the following set of hourly tank levels: 1:00 - 28% 2:00 - 38% 3:00 - 30% 4:00 - 28% 5:00 - 36%
The following data set represents some scores in 10 replications. Based on this daK seft answer...

The following data set represents some scores in 10 replications. Based on this daK seft answer questions Q.1 and 2: 26 56 60 21 11 27 44 23 22 60 Q.1. The data above indicate the number of cars that have been sold by a car dealer in the last 10 weeks. Draw histogram for this data and fill out following table for the same data. Relative Class Frequency 10sx30Frequency 30 sx<50 50 sx<70 Q2.2. Calculate mean and standard deviation...
Question 6 1 pts Calculate Weighted Mean for the following Data: ValueWeight 20 25 32 40...

Question 6 1 pts Calculate Weighted Mean for the following Data: ValueWeight 20 25 32 40 2 4. 4 2 O 29 O 28 O 26 O 30 1 pts What data collection represents this Steam-and- Leaf Diagram? Stems Leaves 2 1, 4 2, 5 0, 3 6, 8 4 5 O 1, 4, 2, 5, 0, 3, 6, 8 02' 1, 4, 3, 2, 5, 4, 0, 3, 5, 6, 8 O 12, 42, 23, 53, 04, 34, 65,...

Consider the following set of data. (19, 11), (26, 53), (65, 28), (77, 20), (108, 56),...

Consider the following set of data. (19, 11), (26, 53), (65, 28), (77, 20), (108, 56), (118, 11) (a) Calculate the covariance of the set of data. (Give your answer correct to two decimal places.) A = -5.63 (b) Calculate the standard deviation of the six x-values and the standard deviation of the six y-values. (Give your answers correct to three decimal places.) sx = sy = (c) Calculate r, the coefficient of linear correlation, for the data in part...