Question

1. A 2-H INDUCTOR DRIVES A CURRENT OF 0.5 AMP WHEN THE CIRCUIT IS OPENED THE CURRENT DISAPPEARS IN 0.01 SEC, CALCULATE THE EMF.

2. CALCULATE THE MAGNETIC FLOW THROUGH A COIL OF 7.2 Mh WITH 300 ROLLS WHEN i=10 mAmp

3. THE CURRENT IN A 0.02-H INDUCTOR VARY ACCORDING TO I-3t 4t CALCULATE
a. Emf at t=1 sec and t = 5 sec
b. So that the value of t the Emf induced is zero

4. A SOLENOID HAS 120 TURNS, IT IS PLACED IN A BASE OF 10mm DIAMETER CALCULATE THE INDUCTANCE L

5. CALCULATE INDUCTANCE IN A CIRCUIT RL WHERE R = 0.4 OHMS AND THE CURRENT INCREASES A % OF ITS FINAL VALUE AT t = 1.5 sec

6. A 12-VOLT BATTERY IS CONNECTED IN SERIES WITH A RESISTANCE R AND AN INDUCTOR L, THE CIRCUIT HAS T 500 sec AND THE MAXIMUM CURRENT Imax 200 mA CALCULATE THE VALUE OF L

7. CALCULATE THE ENERGY ASSOCIATED WITH THE MAGNETICOB FIELD OF A SOLENOID OF 200 TURNS AND CURRENT I = 1.75 AMP PRODUCES A FLOW = 3.7 X 10

8. A BATTERY OF £ = 15 VOLTS IS CONNECTED WITH AN INDUCTOR L 0.6-HYR = 7 OHMS WHEN i = i / 2 , CALCULATE U (energy) TOTAL IN THE INDUCTOR

9. UNL 1.05H IS CONNECTED IN SERIES WITH A VARIABLE CAPACITOR, THE SYSTEM FREQUENCY IS 96.3 MHZ, CALCULATE THE C VALUE

Answer 1

Solution) L = 2 H

i = 0.5 A

t = 0.01 s

E = ?

E = (L)(di/dt)

E = (2)(0.5/0.01)

E = 100 V

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