A solution is prepared by dissolving sucrose, C12H22O11, in water at 25 degrees Celsius. The mol fraction of water is ‘9958. What is the vapor pressure of the solution if the vapor pressure of water at 25 degrees celsius is 23.76 mmHg.
Given that
the solution is made by dissolving sucrose ( non-volatile, non-electrolyte solute) in water.
So, the vapor pressure of the solution depends only the solvent.
According to raoult law, if a non-volatile solute is dissolved in water, the vapor pressure of the solution is
p = mole fraction of solvent (water) × vapor pressure of pure solvent (water)
Given that mole fraction of water = 0.9958
p = 0.9958 × 23.76 mm Hg = 23.66021 mm Hg = 23.66 mm Hg
Vapor pressure of the solution = 23.66 mm Hg
A solution is prepared by dissolving sucrose, C12H22O11, in water at 25 degrees Celsius. The mol...
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