Question

Consider the following hypothesis test with

nequals=16

sequals=6.6

and

x overbarxequals=60.9

H0​:	muμ	equals=	57
HA​:	muμ	not equals≠	57
	alphaα	equals=	0.01

a. State the decision rule in terms of the critical value of the test statistic.

b. State the calculated value of the test statistic.

c. State the conclusion.

a. State the decision rule. Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Round to two decimal places as​ needed.)

A.Reject the null hypothesis if the calculated value of the test statistic is greater than the critical value of

nothing.

​Otherwise, do not reject.

B.Reject the null hypothesis if the calculated value of the test statistic is less than the critical value of

nothing

or greater than the critical value of

nothing.

​Otherwise, do not reject.

C.Reject the null hypothesis if the calculated value of the test statistic is less than the critical value of

nothing.

​Otherwise, do not reject.

b. State the calculated value of the test statistic.

▼

t

z

equals=nothing ​(Round to two decimal places as​ needed.)

c. State the conclusion. Choose the correct answer below.

A. Do not reject the null hypothesis. There is not sufficient evidence that the mean is not equal to 57

B. Reject the null hypothesis. There is not sufficient evidence that the mean is not equal to 57.

C. Reject the null hypothesis. There isis sufficient evidence that the mean is not equal to 57

D.Do not reject the null hypothesis. There is sufficient evidence that the mean is not equal to57

Answer 1

This is a two tailed test

a)

critical value ;-2.947 and 2.947

Decision rule:

Reject the null hypothesis if the calculated value of the test statistic is less than the critical value of -2.947 or greater than the critical value of 2.947

b)

t = (xbar -mu)/(s/sqrt(n))
= ( 60.9 - 57)/(6.6/sqrt(16))
= 2.364

c)

A. Do not reject the null hypothesis. There is not sufficient evidence that the mean is not equal to 57