A wave has the form
y = A cos(2πx/λ0 + π/4) when x < 0.
For
x > 0,
the wavelength is
5λ0/7.
By applying continuity conditions at
x = 0,
find the amplitude Ax > 0 (in terms of A) and phase ϕ of the wave in the region
x > 0.
(Use any variable or symbol stated above as necessary.)
|
ϕ = |
35.5° |
|
Ax > 0 = |
? (0.87 was incorrect) |
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). Part A Find the amplitude. Part B Find the period Part C Find the frequency Part D Find the wavelength Part E Find the speed of propagation. Part F Is the wave traveling in the +x- or − x-direction?
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For 0 x π , 0S9, π , and 120 , solve the 2-D wave equation subject to the following conditions. u(0,y,t)-0, u(T.yt):0, u(x,0,) u(x,π, t) 0, 0 Boundary condition: C11 1 u(x),0)-sin(x)sin(2y) + sin(2x)sin(4y), 0 at It=0 Initial condition:
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A simple harmonic oscillator at the position x=0 generates a
wave on a string. The oscillator moves up and down at a frequency
of 40.0 Hz and with an amplitude of 3.00 cm. At time t =
0, the oscillator is passing through the origin and moving down.
The string has a linear mass density of 50.0 g/m and is stretched
with a tension of 5.00 N.
A simple harmonic oscillator at the position x = 0 generates a wave...