Question

At this time, you need to create menu driven program. The menu includes the following list. The menu should keep showing if a wrong choice is selected until one of the choices of 1 to 4 is selected. After each of the options 1 to 3 is done, the program shows the menu and waits for the user's choice.

Upload your code here.

1. Add odd numbers from a to b

2. Add even numbers from a to b

3. Show multiples of c from a to b

4. Exit

language is java

Answer 1

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import java.util.Scanner;

public class Exercise{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int choice=1, a=0, b=0, c=0;

do{

System.out.println("MENU");

System.out.println("1. Add odd numbers from a to b");

System.out.println("2. Add even numbers from a to b");

System.out.println("3. Show multiples of c from a to b");

System.out.println("4. Exit");

System.out.print("Your choice: ");

choice = scnr.nextInt();

if(choice==1 || choice==2 || choice==3){

System.out.print("Enter a: ");

a = scnr.nextInt();

System.out.print("Enter b: ");

b = scnr.nextInt();

}

switch(choice){

case 1:

{

int sum = 0;

for(int i=a; i<=b; i++){

if(i%2==1)

sum += i;

}

System.out.println("Sum is: "+sum);

}

break;

case 2:

{

int sum = 0;

for(int i=a; i<=b; i++){

if(i%2==0)

sum += i;

}

System.out.println("Sum is: "+sum);

}

break;

case 3:

{

System.out.print("Enter c: ");

c = scnr.nextInt();

System.out.print("Multiples of "+c+" is:");

for(int i=a; i<=b; i++){

if(i%c==0)

System.out.print(" "+i);

}

}

break;

case 4:

System.out.println("Exiting...");

break;

default:

System.out.println("Invalid Choice! Try again...");

break;

}

System.out.println();

}while(choice!=4);

}

}