Question

please help me using C++ to solve the problem below

Use the bisection algorithm to find an approximate solution z to the equation
x^​(5.3) + (3.5)^x = N where N is your 7-digit phone number, and:
(a) z is correct to 2 significant figures.
(b) z is correct to 2 decimal places.

Answer 1

`Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

1)

#include<iostream>
#include<cstdlib>
#include<cmath>
using namespace std;
#define EPSILON 0.01
const int N=1234567;
// An example function whose solution is determined using
// Bisection Method. The function is x^3 - x^2 + 2
double func(double x)
{
return pow(x,5.3)+pow(3.5,x)-(double)N;
}

// Prints root of func(x) with error of EPSILON
void bisection(double a, double b)
{
if (func(a) * func(b) >= 0)
{
cout << "You have not assumed right a and b ";
return;
}

double c = a;
while ((floor(b)-floor(a))!=0)
{
// Find middle point
c = (a+b)/2;

// Check if middle point is root
if (func(c) == 0.0)
break;

// Decide the side to repeat the steps
else if (func(c)*func(a) < 0)
b = c;
else
a = c;
}
cout << "The value of root is : " << c;
}

// Driver program to test above function
int main()
{
// Initial values assumed
double a =0, b = N;
bisection(a, b);
return 0;
}

2)

#include<iostream>
#include<cstdlib>
#include<cmath>
using namespace std;
#define EPSILON 0.01
const int N=1234567;
// An example function whose solution is determined using
// Bisection Method. The function is x^3 - x^2 + 2
double func(double x)
{
return pow(x,5.3)+pow(3.5,x)-(double)N;
}

// Prints root of func(x) with error of EPSILON
void bisection(double a, double b)
{
if (func(a) * func(b) >= 0)
{
cout << "You have not assumed right a and b ";
return;
}

double c = a;
while ((b-a) >= EPSILON)
{
// Find middle point
c = (a+b)/2;

// Check if middle point is root
if (func(c) == 0.0)
break;

// Decide the side to repeat the steps
else if (func(c)*func(a) < 0)
b = c;
else
a = c;
}
cout << "The value of root is : " << c;
}

// Driver program to test above function
int main()
{
// Initial values assumed
double a =0, b = N;
bisection(a, b);
return 0;
}

Kindly revert for any queries

Thanks.