Consider the following 128-bit plaintext block FA 41 4D FF 14 37
33 3C 67 78 89 EC 89
6A BD D6. Rewrite the block as a 4x4 matrix using the column major
format in order to
obtain the initial AES "state".
Consider the following 128-bit plaintext block FA 41 4D FF 14 37 33 3C 67 78...
From the following hexdump, answer the questions below: 0000 00 1d 6b 99 98 68 00 1d d9 2e 4f 61 08 00 45 00 0010 01 41 44 90 40 00 3f 06 d6 5a c0 a8 01 40 4a 7d 0020 13 67 98 f1 01 bb 2e cb 07 05 fb dd 38 75 80 18 0030 ff ff 02 16 00 00 01 01 08 0a 2a 7b 63 c9 3b 78 0040 e0 8b 8d...