Question

Write a program that asks the user to type an even number or 111 to stop. When the user types an even number, display the message “Great Work”, and then ask for input again. When the user types an odd number, display the message “Try again” and ask the user to enter again. When the user enters the sentinel value of 111 the program ends

I've attempted this but it went horribly wrong. we are only suppose to use while, do while, or for loops

#include<stdio.h>
int main()
{
int number,a=0;
printf("press 111 when you want the program to stop\n");
do{

   printf("enter in an even number: ");
   scanf("%d",&number);
  
   if (a=number%2)
   {
       printf("Great work");
   }
   else if (number%2 !=0)
   {
       printf("Try Again");
   }
}
   while(number!=111);
  
}

Answer 1

#include<stdio.h>

int main() {
    int number;
    printf("press 111 when you want the program to stop\n");
    do {
        printf("enter in an even number: ");
        scanf("%d", &number);
        if (number != 111) {
            if (number % 2 == 0) {
                printf("Great work");
            } else {
                printf("Try Again");
            }
        }
    } while (number != 111);

}