Question

Given that: C2H2 (g) + 2 H2O (g) → C2H6O2 (l)   ∆H° = - 198 kJ...

Given that:

C2H2 (g) + 2 H2O (g) → C2H6O2 (l)   ∆H° = - 198 kJ

calculate ∆H°, in kJ, for the reaction

C2H2 (g) + 2 H2O (l) → C2H6O2 (l)

(∆H°f values: H2O (l) = -286, H2O (g) = - 242)

  • A. 154
  • B. -110
  • C. - 286

  • D. - 242
  • E. - 154
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