Hydrogen gas is prepared in the laboratory by reacting
dilute HCl with granulated zinc. Following reaction takes
place. Zn + 2HCl → ZnCl2 + H2 Calculate the volume of
hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl.
1 mol of a gas occupies 22.7 L volume at STP; atomic mass of Zn =
65.3 u.Read more on Sarthaks.com -
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Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction...
Q2 part1. Hydrogen gas can be readily prepared by reacting zinc metal with hydrochloric acid: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) A sample of zinc metal was decomposed in hydrochloric acid and the hydrogen gas was collected over water. The volume of gas collected is 0.798 L at 25oC and a total pressure of 735 torr. How many grams of zinc were decomposed assuming there is an excess of hydrochloric acid? [Hint: the vapor pressure of water at 25oC...
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many grams of zinc would you start with if you wanted to prepare 5.05 L of H2 at 260 mm Hg and 26.0 Celsius?
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many liters of H2 would be formed at 680 mm Hg and 17 ∘C if 27.0 g of zinc was allowed to react? How many grams of zinc would you start with if you wanted to prepare 6.00 L of H2 at 400 mm Hg and 35.0 ∘C?
Hydrogen gas is produced by the reaction of hydrochloric acid, HCl, on zinc metal. 2HCl (aq) + Zn (s) --> ZnCl2 (aq) + H2 (g) The gas is collected over water. If 106 mL of gas is collected at 28C and 775 mmHg, what is the mass of hydrogen collected? (vapor pressure of water at 28C is 25.6 mmHg)
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) Part A: How many liters of H2 would be formed at 538 mm Hg and 16∘C if 22.0 g of zinc was allowed to react? Part B: How many grams of zinc would you start with if you wanted to prepare 5.65 L of H2 at 350 mm Hg and 34.5 ∘C?
zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)ZnCl2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 745 mm Hg. If the wet H2 gas formed occupies a volume of 9.32 L, the number of moles of Zn reacted was __mol. The vapor pressure of water is 17.5 mm Hg at 20 °C.
Zinc reacts with hydrochloric acid to form hydrogen gas. A 0.258 g sample of Zinc reacts with 25.0 mL of 0.250 M HCI solution. What volume does the hydrogen has formed occupy at 24.0 °C and 0.990 atm? Zn(s) + 2HCl(aq) --ZnCl2(aq) + H2(g) 33.0 mL 97.3 mL 6.21 mL 77.0 mL
2. How many liters of hydrogen (Hz) gas can be produced from the reaction of 0.750 g of zinc (Zn) metal with excess HCl at STP. Zn (s) + 2 HCl(aq) + H2(g) + ZnCl2 (aq)
In the laboratory, hydrogen gas is usually made by the following reaction: Zn(s) + 2 HCl(aq) → H2(g) + ZnCl2(aq) How many liters of H2 gas, collected over water at an atmospheric pressure of 752 mm Hg and a temperature of 21.0°C, can be made from 1.566 g of Zn and excess HCl? The partial pressure of water vapor is 18.65 mm Hg at 21.0°C.
determine how many grams of hydrogen gas are produced from 27.2 g
of HCl
4. Zinc metal reacts with hydrochloric acid giving off hydrogen gas, H2 according to the equation: H2() ZnCl2 (aq) + Zn )+2HCI (n) Balance the equation b. Determine how many moles of zinc are required to produce 6.25 moles of hydrogen gas? Imol Zn Imol ta Le.25 mol tH Le 25 me Zn c. Determine how many grams of zinc are required to produce 4.5 moles...