Question

What is the output of the following code? (Note that there are no endl's, all output is on a single line)
      
string s = "Super!";

cout << s.size() << '-';
cout << s.find("er") <<'-';
cout << s.at(3) << '-';
cout << s.erase(2, 1) << '-';
cout << s.insert(2, "wow") << '-';
cout << s.substr(2, 3) << endl;

Answer 1

Output:  6-3-e-Suer!-Suwower!-wow

Explanation:

String	S	u	p	e	r	!
Index	0	1	2	3	4	5

• s.size() ==> returns size of string "Super!" which is equal to 6.
• s.find("er")==>returns the location where string "er" starts. So it outputs 3.
• s.at(3) ==> returns value at index 3 which is e.
• s.erase(2, 1) =>erases characters starting with index 2 and 1 indicates number of characters needs to be erased. (2,1) indicates erase characters staring from 2 and 1 indicates erase only character. So it returns "suer!"

String	S	u	e	r	!
Index	0	1	2	3	4

• s.insert(2, "wow") ==>inserts string "wow" at index 2. Which returns "Suwower!"

String	S	u	w	o	w	e	r	!
Index	0	1	2	3	4	5	6	7

• s.substr(2, 3) ==>returns substring of length 3 starting from index 2. So it returns wow