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How many ways can a delegation of 4 Republicans, 3 Democrats, and 1 Independent be selected...

How many ways can a delegation of 4 Republicans, 3 Democrats, and 1 Independent be selected from a group of 7 Republicans, 7 Democrats, and 4 Independents?

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math   Statistics-And-Probability   
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Answer #1

4 republicans can be selected in 7C4 ways
3 democrats can be selected in 7C3 ways
1 independent can be selected in 4C1 ways

Total possible ways are 7C4 * 7C3 * 4C1
= 35 * 35 * 4
= 4900

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