CaC2O4(s) ⬅️➡️ Ca2+(aq) + C2O42-(aq) the Ksp we calculated at equilibrium is 3.0*10-9 Does this reaction...
CaC2O4(s) ⬅️➡️ Ca2+(aq) + C2O42-(aq)
the Ksp we calculated at equilibrium is 3.0*10-9
Does this reaction favor the reactants or products based on the Ksp for this solid? Explain your reasoning.
Homework Answers
Ksp = 3.0*10-9 <<<<1
Ksp = [Ca^2+][ C2O42-] <<<1
thus
we can say that the as the solubility of CaC2O4 is very low.
so
there are maximum CaC2O4 solid.
therefore,
reaction favor the reactants.
Add Answer to:
CaC2O4(s) ⬅️➡️ Ca2+(aq) + C2O42-(aq)
the Ksp we calculated at equilibrium is 3.0*10-9
Does this reaction...
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