Question

(C programing, Not C++) Write a program in C that asks the user to input 10 numbers.

Store these numbers in an array. Then ask the user to input a single number.

Your program should execute a linear search on the array, trying to find that number.

If the number exists in the array, have the program print out which position/element the

number was found at.

If the target number is not in the array, have the program print out a statement to that

effect.

Example:

./a.out

Please enter 10 numbers.

1 2 3 4 5 6 7 8 9 10

Now enter a number to search for.

5

The number 5 was found at element number 4.

./a.out

Please enter 10 numbers.

1 2 3 4 5 6 7 8 9 10

Now enter a number to search for.

11

The number 11 was not found in the array.

Answer 1

#include <stdio.h>

int main()
{
   int n = 10, i, k, res;
   int a[10];
   printf("Please enter 10 numbers.\n");

   for(i = 0;i<n;i++){
      scanf("%d",&a[i]);
   }
   
   printf("Now enter a number to search for.\n");
   scanf("%d",&k);
   
   res = -1;
   for(i = 0;i<10;i++){
      if(a[i] == k){
         res = i;
      }
   }
   
   if(res != -1){
      printf("The number %d was found at element number %d.\n", k, res);
   }
   else{
      printf("The number %d was not found in the array.\n", k);
   }
   
   return 0;
}