Question

1. A bicycle moves from rest at 8.00 m/s in a time of 2.00 seconds. What is its acceleration?

Answer 1

Initial speed of by cycle (v₀) = 0

Time (t) = 2 sec

Final speed (v) = 8 m/s

From equation of motion -

v = v₀ + at

8 = 0 + 2a

  Acceleration (a) = 4 m/s²

Answer 2

To find the acceleration of the bicycle, we can use the equation for acceleration:

$\text{Acceleration}(�)=\frac{\text{Change in velocity}(\mathrm{\Delta }�)}{\text{Time}(�)}$

The initial velocity ($�$) of the bicycle is 0 m/s (as it starts from rest), and the final velocity ($�$) is 8.00 m/s. The time taken ($�$) is 2.00 seconds.

$\mathrm{\Delta }�=�-�=8.00\text{m/s}-0\text{m/s}=8.00\text{m/s}$$�=\frac{8.00\text{m/s}}{2.00\text{s}}=4.00{\text{m/s}}^2$

So, the acceleration of the bicycle is $4.00{\text{m/s}}^2$.