Read 20 integers into an array. Next, use the unique algorithm to reduce the array to the unique values entered by the user. Use the copy algorithm to display the unique values.

public class RemoveDuplicatesArray {
public static int[] removeDuplicates(int[] originalArray) {
int uniqueLength = 0;
boolean duplicateFound;
for (int i = 0; i < originalArray.length; ++i) {
duplicateFound = false;
for (int j = 0; j < i; ++j) {
if (originalArray[i] == originalArray[j]) duplicateFound = true;
}
if (!duplicateFound) {
uniqueLength++;
}
}
int[] result = new int[uniqueLength];
int ind = 0;
for (int i = 0; i < originalArray.length; ++i) {
duplicateFound = false;
for (int j = 0; j < i; ++j) {
if (originalArray[i] == originalArray[j]) duplicateFound = true;
}
if (!duplicateFound) {
result[ind++] = originalArray[i];
}
}
return result;
}
public static void main(String[] args) {
int[] arr = {6, 5, 6, 2, 4, 2, 7};
int[] unique = removeDuplicates(arr);
System.out.print("Array after removing duplicates is: ");
for (int i = 0; i < unique.length; ++i) {
System.out.print(unique[i] + " ");
}
System.out.println();
}
}

Read 20 integers into an array. Next, use the unique algorithm to reduce the array to...
Please help with this C++ problem using Array
Use a one-dimensional array to solve the following problem. Read in 20 numbers, each of which is between 10 and 100. As each number is read validate it and store it in the array. After reading all the values, display only the unique values that the user entered. Make sure you account for the worst case scenario in which all 20 numbers are different. Use the smallest possible array to solve this...
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