what is the probability that of 2 randomly selected traffic fatalities in 2009 at least one...
what is the probability that of 2 randomly selected traffic fatalities in 2009 at least one was alcohol related
Homework Answers
P(alcohol related) = 9820/33800 = 0.29
P(not alcohol related) = 1 - 0.29 = 0.71
P(both are alcohol related)=0.29 * 0.29 = 0.084
P(neither of the two are alcohol related) = 0.71 * 0.71 = 0.504
Ans:
P(at least one was alcohol related) = 0.29 * 0.71 + 0.71 * 0.29 + 0.29 * 0.29 = 0.496
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