A weight of 7 N is located 17 cm from the fulcrum on the beam of...
A weight of 7 N is located 17 cm from the fulcrum on the beam of a simple balance. What weight should be placed at a point 7 cm from the fulcrum on the opposite side in order to balance the system?
Homework Answers
To balance the system, the total torque on one side of the fulcrum must be equal to the total torque on the other side. Torque is calculated as the product of the force and the distance from the fulcrum (lever arm).
Let's assume the unknown weight we need to find is W (in Newtons), and the distance of this weight from the fulcrum is 7 cm.
The given weight is 7 N, and its distance from the fulcrum is 17 cm.
The balance condition can be expressed as:
Total Torque on one side = Total Torque on the other side
(7 N) * (17 cm) = W * (7 cm)
Now, let's solve for W:
(7 N) * (17 cm) = W * (7 cm)
W = (7 N * 17 cm) / (7 cm)
W = 17 N
So, a weight of 17 N should be placed at a point 7 cm from the fulcrum on the opposite side to balance the system.
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