Given that the the sample space s is the ordered pairs
of two whole numbers, the first from one to three and the second
from one to four
It says let the event A=the sum is even and event B= the first
number is prime
so A=?
and B=?
The sample space for given condition
s ={ (1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4)}
The event A : sum is even
A = { (1,1),(1,3),(2,2),(2,4),(3,1),(3,3)} = 6
B = { (2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4)} = 8
Let's first list all the possible outcomes in the sample space S, which consists of ordered pairs of two whole numbers as described:
S = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4)}
Now, we'll define the events A and B based on the given conditions:
Event A: The sum is even. To find the outcomes where the sum of the two numbers is even, we can consider the following pairs: (1, 1), (1, 3), (2, 2), (2, 4), (3, 1), (3, 3). So, Event A consists of the pairs: {(1, 1), (1, 3), (2, 2), (2, 4), (3, 1), (3, 3)}.
Event B: The first number is prime. The prime numbers between 1 and 3 are 2 and 3. So, Event B consists of the pairs: {(2, 1), (2, 2), (2, 3)}.
To summarize: Event A = {(1, 1), (1, 3), (2, 2), (2, 4), (3, 1), (3, 3)} Event B = {(2, 1), (2, 2), (2, 3)}
To find the events A and B as described, let's first list all the ordered pairs in the sample space S:
Sample space S: {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4)}
Event A: The sum is even
For event A, we need to find all the ordered pairs whose sum is an even number.
Pairs with even sum:
(1, 1) → Sum: 1 + 1 = 2 (even)
(1, 3) → Sum: 1 + 3 = 4 (even)
(2, 2) → Sum: 2 + 2 = 4 (even)
(2, 4) → Sum: 2 + 4 = 6 (even)
(3, 1) → Sum: 3 + 1 = 4 (even)
(3, 3) → Sum: 3 + 3 = 6 (even)
Event A: {(1, 1), (1, 3), (2, 2), (2, 4), (3, 1), (3, 3)}
Event B: The first number is prime
For event B, we need to find all the ordered pairs where the first number is a prime number.
Prime numbers from 1 to 3: 2, 3
Pairs with the first number as prime:
(2, 1)
(2, 2)
(2, 3)
(2, 4)
(3, 1)
(3, 2)
(3, 3)
(3, 4)
Event B: {(2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4)}
In summary:
Event A (the sum is even): {(1, 1), (1, 3), (2, 2), (2, 4), (3, 1), (3, 3)}
Event B (the first number is prime): {(2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4)
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