When making a solution of sodium hydroxide and water, a student weighed out an certain amount of sodium hydroxide pellets and dissolved them in an certain amount of water. However, the sodium hydroxide concentration of the resulting solution was lower than the concentration that the student thought they made. What was the problem?
Sodium hydroxide when dry, absorbs moisture from the atmosphere easily. So, the taken sodium hydroxide is not pure. It contains some water. So, the actual mass of pure sodium hydroxide is less than that was dissolved. That's why, the resulting solution has less than expected concentration.
Comment if any problem.
When making a solution of sodium hydroxide and water, a student weighed out an certain amount...
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1) The heat of solution (delta H) For sodium hydroxide is
-44.5 kJ/mol calculate the amount of energy involved when 5.0 g
sodium hydroxide is dissolved in water
2) calculate the change in temperature expected when 5.0 g
sodium hydroxide is dissolved in 50.0 g water using the energy
(Joules) calculated above. (Ccal= 4.5J/g°C, include 4.0g magnetic
stir-bar in the total mass)
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