required torque to open the lid = 2 N.m
since finger pushes like this

so
0.07*F = 2
F = 2/0.07 =28.5714286 N
so force of 28.5714286 N needs to be supplied by finger and thumb to open this jar
Good Luck !! for exam
let me know in a comment if there is any problem or doubts please
wait for me to respond.
a typical jar that has been tightened to a reasonable degree requires 2.0 N•m to open....
power = 3 kW
if need any more information please ask !!!
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What are the instruments that have been utilized for the
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