What is the price of a $25 strike call? Assume S = $23.50, σ = 0.24, r = 0.055, the stock pays a 2.5% continuous dividend and the option expires in 45 days? SHOW WORK PLS A) $0.60 B) $0.50 C) $0.40 D) $0.30
| As per Black Scholes Model | ||||||
| Value of call option = S*N(d1)-N(d2)*K*e^(-r*t) | ||||||
| Where | ||||||
| S = Current price = | 23.5 | |||||
| t = time to expiry = | 0.125 | |||||
| K = Strike price = | 25 | |||||
| r = Risk free rate = | 5.5% | |||||
| q = Dividend Yield = | 2.50% | |||||
| σ = Std dev = | 24% | |||||
| d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2) | ||||||
| d1 = (ln(23.5/25)+(0.055-0.025+0.24^2/2)*0.125)/(0.24*0.125^(1/2)) | ||||||
| d1 = -0.642588 | ||||||
| d2 = d1-σ*t^(1/2) | ||||||
| d2 =-0.642588-0.24*0.125^(1/2) | ||||||
| d2 = -0.727441 | ||||||
| N(d1) = Cumulative standard normal dist. of d1 | ||||||
| N(d1) =0.260246 | ||||||
| N(d2) = Cumulative standard normal dist. of d2 | ||||||
| N(d2) =0.233478 | ||||||
| Value of call= 23.5*0.260246-0.233478*25*e^(-0.055*0.125) | ||||||
| Value of call= 0.32 | ||||||
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