Question

Under certain conditions, the substances bromine and chlorine combine to form bromine monochloride. If 21.6 grams of bromine and 9.6 grams of chlorine combine to form bromine monochloride, how many grams of bromine monochloride must form?

Answer 1

Ans :

Number of moles of bromine = mass / molar mas

= 21.6 g / 79.904 g/mol = 0.27 mol

number of mol of chlorine = mass / molar mass

= 9.6 g / 35.453 g/mol = 0.27 mol

Since equimolar amounts of both the reagents are present , the number of mol of product bromine monochloride formedwill be 0.27 mol

Mass of bromine monochloride = mol x molar mass

= 0.27 mol x 115.357 g/mol

= 31.1 grams