Given two 2-dimensional arrays, A and B, calculate the three arrays: A + B, A*B and A*B-1 . That is to say find the sum of the two arrays, the outer-product of the two arrays and the outer-product of A times B inverse.
You can use the procedure illustrated on the web site:
https://www.thecrazyprogrammer.com/2017/02/c-c-program-find-inverse-matrix.html (Links to an external site.)
C++ Program:
#include <iostream>
#include <iomanip>
using namespace std;
//Printing matrix
void printMatrix(double res[3][3])
{
int i, j;
cout << fixed << setprecision(2);
//Iterating over rows
for(i=0; i<3; i++)
{
//Iterating over columns
for(j=0; j<3; j++)
{
cout << left << setw(6) << res[i][j] << "
";
}
cout << "\n";
}
}
//Matrix Addition
void matrixAddition(double mat1[3][3], double mat2[3][3], double
res[3][3])
{
int i, j;
//Iterating over rows
for(i=0; i<3; i++)
{
//Iterating over columns
for(j=0; j<3; j++)
{
res[i][j] = mat1[i][j] + mat2[i][j];
}
}
}
//Matrix Multiplication
void matrixMultiplication(double mat1[3][3], double mat2[3][3],
double res[3][3])
{
int i, j, k;
//Iterating over rows
for(i=0; i<3; i++)
{
//Iterating over columns
for(j=0; j<3; j++)
{
res[i][j] = 0;
for(k=0; k<3; k++)
{
res[i][j] += mat1[i][k] + mat2[k][j];
}
}
}
}
void inverse(double mat[3][3], double res[3][3])
{
int i, j;
double det=0;
//finding determinant
for(i = 0; i < 3; i++)
{
det = det + (mat[0][i] * (mat[1][(i+1)%3] * mat[2][(i+2)%3] -
mat[1][(i+2)%3] * mat[2][(i+1)%3]));
}
cout << "\n\n Determinant: " << det << "\n\n";
for(i = 0; i < 3; i++)
{
for(j = 0; j < 3; j++)
{
res[i][j] = ((mat[(j+1)%3][(i+1)%3] * mat[(j+2)%3][(i+2)%3]) -
(mat[(j+1)%3][(i+2)%3] * mat[(j+2)%3][(i+1)%3]))/(double)det;
}
}
}
//Main function
int main()
{
//Declaring arrays
double A[3][3] = {{1, 2, 3},{4, 5, 6},{7, 8, 9}};
double B[3][3] = {{3, 0, 2},{2, 0, -2},{0, 1, 1}};
double C[3][3];
double BInv[3][3];
cout << "\n\n Matrix A: \n\n";
printMatrix(A);
cout << "\n\n Matrix B: \n\n";
printMatrix(B);
//Addition
matrixAddition(A, B, C);
cout << "\n\n Matrix C = A+B: \n\n";
printMatrix(C);
//Multiplication
matrixMultiplication(A, B, C);
cout << "\n\n Matrix C = A*B: \n\n";
printMatrix(C);
//Inverse
inverse(B, BInv);
cout << "\n\n Matrix B-1: \n\n";
printMatrix(BInv);
matrixMultiplication(A, BInv, C);
cout << "\n\n Matrix C = A+B-1: \n\n";
printMatrix(C);
cout << "\n\n";
return 0;
}
___________________________________________________________________________________________________
Sample Run:

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