Question

You will need to fill in the body of setLeftBit(). The input will be a byte (i.e., 8 bits) input and a single bit bit, and you will need to set the leftmost bit of input to bit and return the result.

For example, if input is 127 (i.e., 01111111) and bit is 1, the result would be 255 (i.e., 11111111).

Please do the solution in C++ and explain/comment your code. Thanks.

Answer 1

#include <iostream>
#include <cmath>

using namespace std;

int Number;
int arrDig[8] = {128, 64, 32, 16, 8, 4, 2, 1};
int arrCheck[7];
int iTotal = 0;

int setLeftBit(int Number){
if(Number < 0 || Number > 255)
   {
       return 0;
   }

   else

   {
       for(int i=0; i<7; i++)
       {
           if(Number >= (iTotal + arrDig[i]))
           {
               {
                   arrCheck[i] = 1;

                   iTotal = iTotal + arrDig[i+1];

                   if(Number >= iTotal)
                   {
                       arrCheck[i+1] = 1;
                   }

                   else

                   {
                       arrCheck[i] = 0;
                   }
               }
           }

               else

           {
               {
                   {
                       {arrCheck[i] = 0;}
                   }
               }
           }
       }
       cout<<"Before Set Leftmost-bit..";
       cout << arrCheck[0] << arrCheck[1] << arrCheck[2] << arrCheck[3] << arrCheck[4] << arrCheck[5] << arrCheck[6] << arrCheck[7] << "\n" << endl;
   }

   if(arrCheck[0]==1){
arrCheck[0]=0;
cout<<"After Set Leftmost-bit..";
cout << arrCheck[0] << arrCheck[1] << arrCheck[2] << arrCheck[3] << arrCheck[4] << arrCheck[5] << arrCheck[6] << arrCheck[7] << "\n" << endl;
   }
   if(arrCheck[0]==0){
arrCheck[0]=1;
cout<<"After Set Leftmost-bit..";
cout << arrCheck[0] << arrCheck[1] << arrCheck[2] << arrCheck[3] << arrCheck[4] << arrCheck[5] << arrCheck[6] << arrCheck[7] << "\n" << endl;
   }

}

int main()
{
   cout << "Enter the Number: " << endl;
   cin >> Number;

setLeftBit(Number);
   return 1;
}