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Solid silver sulfide and solid iron(III) sulfide are in equilibrium with a solution containing 1.33×10-2 M...

Solid silver sulfide and solid iron(III) sulfide are in equilibrium with a solution containing 1.33×10-2 M iron(III) acetate.

Calculate the concentration of silver ion present in this solution.
[silver] =  M

KSPS=AgBr3.3 × 10-13CarbonatesBaCO38.1 × 10-9

CaCO33.8 × 10-9

CoCO38.0 × 10-13

CuCO32.5 × 10-10

FeCO33.5 × 10-11

PbCO31.5 × 10-13

MgCO34.0 × 10-5

MnCO31.8 × 10-11

NiCO36.6 × 10-9

Ag2CO38.1 × 10-12

ZnCO31.5 × 10-11ChloridesPbCl21.7 × 10-5

AgCl1.8 × 10-1. BaCrO42.0 × 10-10

CaCrO47.1 × 10-4

PbCrO41.8 × 10-14

Ag2CrO49.0 × 10-12 Ni(CN)23.0 × 10-23

AgCN1.2 × 10-16

Zn(CN)28.0 × 10-12  BaF21.7 × 10-6

CaF23.9 × 10-11

PbF23.7 × 10-8

MgF26.4 × 10-9 AgOH2.0 × 10-8

Al(OH)31.9 × 10-33

Ca(OH)27.9 × 10-6

Cr(OH)36.7 × 10-31

Co(OH)22.5 × 10-16

Cu(OH)21.6 × 10-19

Fe(OH)27.9 × 10-15

Fe(OH)36.3 × 10-38

Pb(OH)22.8 × 10-16

Mg(OH)21.5 × 10-11

Mn(OH)24.6 × 10-14

Ni(OH)22.8 × 10-16

Zn(OH)24.5 × 10-1 PbI28.7 × 10-9

AgI1.5 × 10-16 C2O41.1 × 10-7

CaC2O42.3 × 10-9

MgC2O48.6 × 10-5 AlPO41.3 × 10-20

Ba3(PO4)21.3 × 10-29

Ca3(PO4)21.0 × 10-25

CrPO42.4 × 10-23

Pb3(PO4)23.0 × 10-44

Ag3PO41.3 × 10-20

Zn3(PO4)29.1 × 10-3 BaSO41.1 × 10-10

CaSO42.4 × 10-5

PbSO41.8 × 10-8

Ag2SO41.7 × 10-5  CaS8 × 10-6

CoS5.9 × 10-21

CuS7.9 × 10-37

FeS4.9 × 10-18

Fe2S31.4 × 10-88

PbS3.2 × 10-28

MnS5.1 × 10-15

NiS3.0 × 10-21

Ag2S1.0 × 10-49

ZnS2.0 × 10-25 BaSO38.0 × 10-7

CaSO31.3 × 10-8

Ag2SO31.5 × 10-14

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Answer #1

Sol.

As concentration of iron (III) acetate , Fe(CH3COO)3

[Fe(CH3COO)3] = 1.33 × 10-2 M

Concentration of Fe3+ = [Fe3+] = [Fe(CH3COO)3]

= 1.33 × 10-2 M  

Now , Reaction of iron ( III ) sulfide , Fe2S3 :

Fe2S3 ----> 2Fe3+ + 3S2-

Ksp = [Fe3+]2 [S2-]3

1.4 × 10-88 = ( 1.33 × 10-2 )2 [S2-]3  

[S2-]3 = 0.7914 × 10-84

[S2-] = ( 0.7914 × 10-84 )1/3 = 0.9249 × 10-28    M

Now , Reaction of silver sulfide , Ag2S :

Ag2S ----> 2Ag+ + S2-

Ksp = [Ag+]2 [S2-]  

1.0 × 10-49 = [Ag+]2 × 0.9249 × 10-28  

[Ag+] = ( 0.10811 × 10-20 )1/2 = 0.3288 × 10-10 M

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