HomeworkLib
Question

the heights of women aged 18-24 are normally distributed with mean 64.5 inches and a standard...

the heights of women aged 18-24 are normally distributed with mean 64.5 inches and a standard deviation of 2.5 inches. Let X denote the height of a woman. Based on the empirical rule (68-95-99.7rule) answer the following

a) P(X<62 or X>69.5)=?

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

.

0 0
Add a comment
Know the answer?
Add Answer to:
the heights of women aged 18-24 are normally distributed with mean 64.5 inches and a standard...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Assume that the heights of women are normally distributed with a mean of 63.6 inches and...

    Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If a woman is randomly selected, what is the probability that her height is between 58 and 80 inches?

  • If the heights of women are normally distributed with a mean of 65.0 inches and a...

    If the heights of women are normally distributed with a mean of 65.0 inches and a standard deviation of 2.5 inches and the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches,   At 71 inches what is the probability for the height of a person of your gender to be within 3 inches of your height (between “your height – 3 inches” and “your height + 3 inches”)?

  • Question 25 5 pts Heights of adult American men are normally distributed with a mean of...

    Question 25 5 pts Heights of adult American men are normally distributed with a mean of 69 inches and a standard deviation of 3 inches. Using the Empirical rule, approximately what percentage of men have heights below 63 inches? 68% O O O 95% 5% 2.5% Question 26 5 pts Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. Find the value of the quartile Q3. 66.1...

  • Assume that the heights of women are normally distributed with a mean of 63.6 inches and...

    Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If 200 women want to enlist in the U.S. Army, how many would you expect to meet the height requirements? About 197 women

  • Women’s heights are normally distributed with mean 63.9 inches and standard deviation 2.8 inches. Men’s heights...

    Women’s heights are normally distributed with mean 63.9 inches and standard deviation 2.8 inches. Men’s heights are normally distributed with mean 68.4 inches and standard deviation 3.0 inches. The US Navy requires that fighter pilots have heights between 62 and 78 inches. Find the percentage of women meeting the height requirement to be a fighter pilot. Find the percentage of men that are too short to be fighter pilots.

  • Assuming that the heights of college women are normally distributed with mean 68 inches and standard...

    Assuming that the heights of college women are normally distributed with mean 68 inches and standard deviation 2.3 inches, answer the following questions. (Hint: Use the figure below with mean μ and standard deviation σ.) (a) What percentage of women are taller than 68 inches? % (b) What percentage of women are shorter than 68 inches? % (c) What percentage of women are between 65.7 inches and 70.3 inches? % (d) What percentage of women are between 63.4 and 72.6...

  • The heights of adult men in America are normally distributed, with a mean of 69.5 inches...

    The heights of adult men in America are normally distributed, with a mean of 69.5 inches and a standard deviation of 2.66 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.8 inches and a standard deviation of 2.51 inches. If a man is 6 feet 3 inches tall, what is his z-score (to 4 decimal places)? z = If a woman is 5 feet 11 inches tall, what is her z-score...

  • Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard...

    Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches. Write your answer as a decimal rounded to 4 places.

  • Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 2.6...

    Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 2.6 inches, answer the following questions. (Hint: Use the figure below with mean and standard deviation o.) Area Under a Normal Curve 34% 34% 13.5% 2.35% (a) What percentage of women are taller than 62 inches? 50 % (b) What percentage of women are shorter than 62 inches? (c) What percentage of women are between 59.4 inches and 64.6 inches? (d) What percentage...

  • In a population of 225 women, the heights of the women are normally distributed with a...

    In a population of 225 women, the heights of the women are normally distributed with a mean of 64.5 inches and a standard deviation of 2.9 inches. If 25 women are selected at a random, find the probability that their mean height will exceed 66 inches. Assume that the sampling is done without replacement and use a finite population correction factor with N=225. Pls. show solution

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT