The concentration of lead ions (Pb2+) in a sample of polluted water that also contains nitrate...
The concentration of lead ions (Pb2+) in a sample of
polluted water that also contains nitrate ions
(NO3−) is determined by adding solid sodium
sulfate (Na2SO4) to exactly 500 mL of the
water. Calculate the molar concentration of Pb2+ if
0.00230 g of Na2SO4 was needed for the
complete precipitation of lead ions as PbSO4.
Homework Answers
The reaction between Pb2+ and Na2SO4 is as follows
Pb2+(aq) + Na2SO4 (aq) ------> PbSO4(s) + 2Na+(aq)
stoichiometrically, 1mole of Na2SO4 react with 1mole of Pb2+
moles of Na2SO4 consumed = 0.00230g/142.04g/mol = 1.62×10-5
number of moles of Pb2+ = 1.62×10-5 mol
molarity of Pb2+ =(1.62 × 10-5mol/500ml)×1000ml
Molarity of Pb2+ = 3.24×10-5 M
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Enter your answer in the provided box. The concentration of lead ions (Pb2) in a sample of polluted water that also contains nitrate ions (NO3 ) is determined by adding solid sodium sulfate (Na2SO4) to exactly 500 mL of the water. Calculate the molar concentration of Pb2* if 0.00275 g of NazSO4 was needed for the complete precipitation of lead ions as Pbso4
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solution. This solution is then added to 165 mL of 0.015 M aqueous
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molarity) of nitrate ions in the solution?
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