Calculate the standard enthalpy of formation of NO(g) (in kJ/mol) from the following data.
N2(g) + 2 O2(g) → 2 NO2(g)
ΔH⁰298
= 66.4 kJ 2 NO(g) + O2(g) → 2 NO2(g)
ΔH⁰298
= −116.2 kJ
On reversing the equation,dH gets changed the sign. That means if forward reaction is endothermic then backward reaction is exothermic.

Calculate the standard enthalpy of formation of NO(g) (in kJ/mol) from the following data. N2(g) +...
The standard enthalpy change for the following reaction is 66.4 kJ at 298 K. N2(g) + 2 O2(g) 2 NO2(g) AH° = 66.4 kJ What is the standard enthalpy change for this reaction at 298 K? 1/2 N2(g) + O2(g) — NO2(g) Submit Answer
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The standard enthalpy change for the following reaction is -66.4 kJ at 298 K. 2NO2 = N2 + 2O2 = -66.4 What is the standard enthalpy change for this reaction at 298 K? 1/2N2 + O2 = NO2
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