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We have X and Y that are exchangeable in the sense that (X,Y) = (Y,X). That...

We have X and Y that are exchangeable in the sense that (X,Y) = (Y,X). That is, their joint pdf f(x,y) satisfies f(x,y) = f(y,x), for all (x,y).

Show that fY-X (y-x) = fY-X -(y-x).

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